(x^2-2x-5)(x-1)-9=0

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Solution for (x^2-2x-5)(x-1)-9=0 equation: 


Simplifying
(x2 + -2x + -5)(x + -1) + -9 = 0

Reorder the terms:
(-5 + -2x + x2)(x + -1) + -9 = 0

Reorder the terms:
(-5 + -2x + x2)(-1 + x) + -9 = 0

Multiply (-5 + -2x + x2) * (-1 + x)
(-5(-1 + x) + -2x * (-1 + x) + x2(-1 + x)) + -9 = 0
((-1 * -5 + x * -5) + -2x * (-1 + x) + x2(-1 + x)) + -9 = 0
((5 + -5x) + -2x * (-1 + x) + x2(-1 + x)) + -9 = 0
(5 + -5x + (-1 * -2x + x * -2x) + x2(-1 + x)) + -9 = 0
(5 + -5x + (2x + -2x2) + x2(-1 + x)) + -9 = 0
(5 + -5x + 2x + -2x2 + (-1 * x2 + x * x2)) + -9 = 0
(5 + -5x + 2x + -2x2 + (-1x2 + x3)) + -9 = 0

Combine like terms: -5x + 2x = -3x
(5 + -3x + -2x2 + -1x2 + x3) + -9 = 0

Combine like terms: -2x2 + -1x2 = -3x2
(5 + -3x + -3x2 + x3) + -9 = 0

Reorder the terms:
5 + -9 + -3x + -3x2 + x3 = 0

Combine like terms: 5 + -9 = -4
-4 + -3x + -3x2 + x3 = 0

Solving
-4 + -3x + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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